Ohio gubernatorial election
1846 Ohio gubernatorial election
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← 1844 | 13 October 1846 | 1848 → |
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| | | Nominee | William Bebb | David Tod | | Party | Whig | Democratic | Popular vote | 118,869 | 116,484 | Percentage | 48.28% | 47.31% | |
Governor before election Mordecai Bartley Whig | Elected Governor William Bebb Whig | |
Elections in Ohio |
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The 1846 Ohio gubernatorial election was held on 13 October 1846, in order to elect the Governor of Ohio. Whig nominee William Bebb defeated Democratic nominee David Tod and Liberty nominee Samuel Lewis.[1]
General election
On election day, 13 October 1846, Whig nominee William Bebb won the election by a margin of 2,385 votes against his foremost opponent Democratic nominee David Tod, thereby retaining Whig control over the office of Governor. Bebb was sworn in as the 19th Governor of Ohio on 12 December 1846.[2]
Results
Ohio gubernatorial election, 1846 Party | Candidate | Votes | % |
| Whig | William Bebb | 118,869 | 48.28% |
| Democratic | David Tod | 116,484 | 47.31% |
| Liberty | Samuel Lewis | 10,797 | 4.39% |
| | Scattering | 46 | 0.02% |
Total votes | 246,196 | 100.00% |
| Whig hold |
References